2 Different C and C++ Programs to Check Whether a Given String is Palindrome or Not

Here i am writing two different programs to check whether a given string (text) us palindrome or not. There are C and C++ programs for this.

C Programs:

(i) Using string functions:

#include<stdio.h>
#include<string.h>
#include<conio.h>
void main()
{
char a[100],b[100];
printf("Enter the string to check if palindrome or not\n");
gets(a);
strcpy(b,a);
strrev(b);
if(strcmp(a,b)==0)
printf("\nEntered string is palindrome");
else
printf("\nEntered string is not palindrome");
getch();
} 

(ii) Comparing Character by Character

#include<string.h>
#include<stdio.h>
#include<conio.h>
void main()
{
int len,i;
char a[100];
printf("Enter the string to check whether it is palindrome or not\n");
gets(a);
len=strlen(a);
for(i=0;i<len/2;i++)
{
if(a[i]!=a[len-i-1])
break;
}

if(i==len/2)
printf("\nEntered string is palindrome");
else
printf("\nEntered string is not palindrome");
getch();
}

C++ Programs:

(i) Using String functions:

C and C++ Programs to Check Whether a Given Number is Armstrong Number or Not

This post contains two programs, a C++ program and a C program. These are programs to check whether a given number is an Armstrong number or not. An Armstrong number is a positive integer for which the sum of 'n'th power of all of its digits is equal to the number itself. For example, 153 is a 3 digit Armstrong number because 1³+5³+3³=153.

C ++ program:

# include <iostream.h>

# include <conio.h>

# include <math.h>

void main ()

{

clrscr();

int a,b=0,sum=0;

long int n;

cout<<"Enter the number to be checked\n ";

cin>>n;

if(n<1)
{
cout<<"\nThe number should be greater than 0";
}
else
{
a=n;
//counting the digits
while (a>0) 
{
a=a/10; 
b++;
}
a=n;
//adding up bth power of digits
while(a>0)
{
sum=sum+pow(( a%10) ,b);
a=a/10;
}
if(sum==n)
cout<<"\nThe number is an ARMSTRONG number";
else
cout<<"\nThe number is NOT an ARMSTRONG number";
}
getch();
}

C Program:

# include <stdio.h>

# include <conio.h>

# include <math.h>

void main ()

{

clrscr();

int a,b=0,sum=0;

long int n;

printf("Enter the number to check\n ");

scanf("%i",&n);
if(n<1)
{
printf ("\nThe number should be greater than 0");
}
else
{
a=n;
//counting the digits
while (a>0) 
{
a=a/10; 
b++;
}
a=n;
//adding up bth power of digits
while(a>0)
{
sum=sum+pow(( a%10) ,b);
a=a/10;
}
if(sum==n)
printf ("\nThe number is an ARMSTRONG number");
else
printf ("\nThe number is NOT an ARMSTRONG number");
}
getch();
}